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In the winter sport of curling, players give a 20kg stone a push across a sheet of ice. A curler accelerates a stone to a speed of 3.1m/s over a time 2.2s
a) How much force does the curler exert on the stone?
b) What average power does the curler use to bring the stone up to speed?
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To find force, you need to know acceleration. To find that, you can use the final velocity equation:

Vfinal = Vinitial + a*t
3.1 = 0 + 2.2a
a = 1.409

F = ma = 1.409*20 = 28.18N

Average power is the value of the total work done divided by the time it took to do the work.

Work = Force*Distance, so we need distance. We can use the displacement equation.

x = Vinitial*t + (1/2) at^2
x = 0 + (1/2) (1.409)(2.2)^2
x = 3.40978 m

Work = F*d = 28.18*3.40978 = 96.0876 J

Average Power = W / t = 96.0876 / 2.2 = 43.676 watts
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