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In the winter sport of curling, players give a 20kg stone a push across a sheet of ice. A curler accelerates a stone to a speed of 3.1m/s over a time 2.2s

a) How much force does the curler exert on the stone?

b) What average power does the curler use to bring the stone up to speed?

Added Wed, 08 Jul '15

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To find force, you need to know acceleration. To find that, you can use the final velocity equation:

Vfinal = Vinitial + a*t

3.1 = 0 + 2.2a

a = 1.409

F = ma = 1.409*20 = 28.18N

Average power is the value of the total work done divided by the time it took to do the work.

Work = Force*Distance, so we need distance. We can use the displacement equation.

x = Vinitial*t + (1/2) at^2

x = 0 + (1/2) (1.409)(2.2)^2

x = 3.40978 m

Work = F*d = 28.18*3.40978 = 96.0876 J

Average Power = W / t = 96.0876 / 2.2 = 43.676 watts

Added Wed, 08 Jul '15

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