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A proton moving with speed 3.45*10<5 m/s in a field-free region enters an essentially uniform magnetic field of magnitude 0.795 T perpendicular to the velocity of the proton. If the proton enters the magnetic field region at a 60.0 degree celsius angle , (a) At what angle does it leave , and (b) at what distance Y does it exit the field?
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(a) it leaves at 60 degrees due to symmetry

(b) distance y=radiius of the circle = mv/qB

y= 4.53 mm
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