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A toy rocket, launched from the ground, rises vertically with an acceleration of 16m/s2 for 2.7s until its motor stops. Disregarding any air resistance, what maximum height above the ground will the rocket achieve? The acceleration of gravity is 9.8 m/s2 .

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when plane accelrates :

h1 = ut + at^2 /2 = 0 + 16 x 2.7^2 /2 = 58.32 m

velocity when engine turn off

v = u +at = 0 + 16 x 2.72 = 43.52 m/s

after that using v^2 - u^2 = 2aH

0 - 43.52^2 = 2 x(-9.8) X h2

h2 =96.63 m

H = h1+h2 = 154.95 m

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