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The decay of a fictitious nucleus is accompanied by the emission of a gamma ray with wavelength 2.48x10^-2 nm. This decay is due to the transition between two energy levels. What is the difference between these two levels?
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Energy difference = h c / lambda

where lambda = wavelength = 2.48*10^-2 nm

= 2.48*10^-11 m

Energy difference =  h c / lambda

= (6.634*10^-34 * 3 * 10^8 ) / (  2.48*10^-11 )

= 8.025 * 10^-15 J

= (  8.025 * 10^-15 ) /( 1.6 *10^-19)

= 50156.25 eV

= 5.01 x 10^-2 MeV
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