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A 53.0-kg person jumps from rest from the top of a 10.0-m-high tower straight down into the water. Neglect air resistance. She comes to rest 3.00 m under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.
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MGH = MGH + Wnc
(53.0)(9.8)(10) = (53.0)(9.8)(-3.00) + Wnc
5194 = -1558 + wnc
6752 = Wnc

W=FD
6752= F(3)
6752/3 = F
2250.67 N = F
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