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An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of + 20.6 m/s and measures a time of 20.9 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? (positive = up, negative = down)

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u(initial velocity )= 20.6 up= +20.6

when it reach back it will have same speed as initial but in down ward direction

v (final velocity)= 20.6 down = -20.6

let g is acceleration due to gravity is g

v-u= gt 1st equation of motion

-20.6- 20.6=g*20.9

=> g= -1.9713 m/s^2 hence direction is down and magnitude is 1.9713

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