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A parallel-plate capacitor is formed from two 5.0cm -diameter electrodes spaced 2.9mm apart. The electric field strength inside the capacitor is 5.0 *106N/C.

What is the charge (in nC) on each electrode?

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Added Tue, 29 Dec '15
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Capacitance C of a parallel palte capacitor is given by C = KeoA/d

where A = area = pi r^2,

e0 = constnat = 8.85*10^-12,

d = distance between the plates,

K = dieelctric constant (=1 for air)

Chareg Q = CV where V = Volatge

also EF E = V/d

so E = Q/eoA

charge Q = E eo A

Q = 5e6 * 8.85e-12 * (3.14* 0.025*0.025)

Q = 86.84 nC

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Added Tue, 29 Dec '15
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