ToughSTEM
Sign Up
Log In
ToughSTEM
A question answer community on a mission
to share Solutions for all STEM major Problems.
Cant find a problem on ToughSTEM?
0

A new landowner has a triangular piece of flat land she wishes to fence. Starting at the west corner, she measures the first side to be 80 m long and the next to be 105 m -- these sides are represented as displacement vectors A and B in Figure 3.26, where θ1=19°, and θ2=12°. She then correctly calculates the length and orientation of the third side C. What is her result?

Find the magnitude and the direction south of west

Edit
Added Mon, 14 Dec '15
Comment
Add a Comment
Solutions
0

A) Y = 80 * SIN 19 = - 26.045

A) X = 80 * COS 19 = 75.64

B) Y = 105 * COS 12 = 102.71

B) X = 105 * SIN 12 = -21.831

TOTAL Y = 102.71 - 26.045 = +76.67

TOTAL X = 75.64 - 21.831 = +53.81

Third Side : C) = SQRT (76.67.^2 + 53.81^2) = 93.69 Meters length

Third Side : C) Angle = ARC TAN 76.67 / 53.81 = 54.97 degrees North of Due West

from the West Corner

Edit
Added Mon, 14 Dec '15
Comment
Add a Comment
Add Your Solution!
Close

Click here to
Choose An Image
or
Get image from URL
GO
Close
Back
Add Image
Close
What URL would you like to link?
GO
α
β
γ
δ
ϵ
ε
η
ϑ
λ
μ
π
ρ
σ
τ
φ
ψ
ω
Γ
Δ
Θ
Λ
Π
Σ
Φ
Ω
Copied to Clipboard

Add Your Solution
Sign Up
to interact with the community. (That's part of how we ensure only good content gets on ToughSTEM)
OR
OR
ToughSTEM is completely free, and its staying that way. Students pay way too much already.
Almost done!
Please check your email to finish creating your account!
Welcome to the Club!
Choose a new Display Name
Only letters, numbers, spaces, dashes, and underscores, are allowed. Can not be blank.
Great! You're all set, .
A question answer community on a mission
to share Solutions for all STEM major Problems.
Why
The Purpose
How
The Community
Give Feedback
Tell us suggestions, ideas, and any bugs you find. Help make ToughSTEM even better.