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An object with a charge of -3.1\mu C and a mass of 1.0*10^-2 kg experiences an upward electric force, due to a uniform electric field, equal in magnitude to its weight. Find the magnitude of the electric field. Find the direction of the electric field If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration. If the electric charge on the object is doubled while its mass remains the same, find the direction and magnitude of its acceleration.

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Added Mon, 14 Dec '15
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Fe = Fg

q*E = m*g

E = m*g/q

= 1*10^-2*9.8/3.1*10^-6

= 3.0625*10^4 N/c (downward)

when charge becomes double

Fnet = 2*q*E - m*g

m*a = 2*q*E - m*g

= 2*(m*g) - m*g

= g

= 9.8 m/s^2

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Added Mon, 14 Dec '15
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