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An air bubble has a volume of 1.30 cm3 when it is released by a submarine 100 m below the surface of a lake. What is the volume of the bubble when it reaches the surface? Assume the temperature and the number of air molecules in the bubble remain constant during its ascent.

cm3
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According to the ideal gas law,
P1V1/T1 = P2V2/T2 (But T1 =T2)

=> P1V1 = P2V2

P1( water pressure below 120 m)

100m/ 10m/ ATM = 10 ATM

10 ATM + 1 ATM( pressure on surface by air pressure)
= 11ATM

V1 = 1.30 cm3

P2( surface pressure ) = 1 ATM ( pressure on surface by air pressure)

Thus, 11 ATM x 1.30 cm3 = 1ATM x X cm3

X cm3( you want to know) = 14.3 cm3

The bubble volume will be 14.3 cm3 at the water surface.
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