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Suppose that you wish to fabricate a uniform wire out of 0.850 g of copper. Assume the wire has a resistance R = 0.600 ?, and all of the copper is used.

(a) What will be the length of the wire?

(b) What will be the diameter of the wire?
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apply density = mass/volume
density of copper = 8900 Kg/m^3
so Volume = (A*L) = 0.850*10^-3 /8900
V = AL = 9.55*10^-8 m^3---------------------------------------1
now apply Resistance R = rho L/A
so L/A = 0.6/1.68*10^-8 = 0.357*10^8 -----------------------2
now divide 1 and 2
A^2 = 9.55*10^-8/0.357 *10^8
A^2 = 26.74*10^-16
A = 5.17 *10^-8
A = pi r^2 = 5.17 *10^-8
r^2 =1.646*10^-8
r = 1.28 *10^-4 m
diameterr = 2.566 *10^-4 m

----------------------------------

multiply 1 and 2
L^2= 9.55*0.357
L^2 = 3.40935
L = 1.846 m
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