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Suppose that you wish to fabricate a uniform wire out of 0.850 g of copper. Assume the wire has a resistance R = 0.600 ?, and all of the copper is used.

(a) What will be the length of the wire?

(b) What will be the diameter of the wire?  Edit
Added Fri, 03 Jul '15 Community
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apply density = mass/volume
density of copper = 8900 Kg/m^3
so Volume = (A*L) = 0.850*10^-3 /8900
V = AL = 9.55*10^-8 m^3---------------------------------------1
now apply Resistance R = rho L/A
so L/A = 0.6/1.68*10^-8 = 0.357*10^8 -----------------------2
now divide 1 and 2
A^2 = 9.55*10^-8/0.357 *10^8
A^2 = 26.74*10^-16
A = 5.17 *10^-8
A = pi r^2 = 5.17 *10^-8
r^2 =1.646*10^-8
r = 1.28 *10^-4 m
diameterr = 2.566 *10^-4 m

----------------------------------

multiply 1 and 2
L^2= 9.55*0.357
L^2 = 3.40935
L = 1.846 m  Edit
Added Fri, 03 Jul '15 Community
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