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Four acrobats of mass 75.5 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 75.5-kg acrobat is at the bottom of the tower.

(a) What is the normal force acting on the 75.5-kg acrobat?
_______N

(b) If the area of each of the 75.5-kg acrobat's shoes is 475 cm2, what average pressure (not including atmospheric pressure) does the column of acrobats exert on the floor?
_______Pa

(c) Will the pressure be the same if a different acrobat is on the bottom? Explain.
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Added Fri, 03 Jul '15
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a)
The force on his shoulders is (68+62+55)kg*9,81 m/s^2 = 1814,85 N
and on his feet 266,9*9.81 = 2618.3 N

b)
The area of both feet is 950cm^2 = 9.5*10^2 cm^2 = 9.5*10-2 m^2
The pressure is
2618.3 N/9.5*10^-2 m^2 = 275.61*10^2 Pascal

c)
Only if the other person has the same shoe size

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Added Fri, 03 Jul '15
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