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A glass flask whose volume is 1000cm3 at 0.0 ?Cis completely filled with mercury at this temperature. When flask and mercury are warmed to 56.0?C, 8.90cm3 of mercury overflow.

Part A

If the coefficient of volume expansion of mercury is 1.80*10^-4K^1 , compute the coefficient of volume expansion of the glass.

Express your answer using two significant figures.

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Edited Sat, 21 Nov '15
Added Sat, 21 Nov '15
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Original volume of mercury = 1000 cm3.

The final volume of mercury considering its volume expansion quotient = 1000 + 1000*(1.8*10^-4 *56) = 1000 + 10.08 = 1010.08 cm^3

Considering the glass as a non expanding substance, the complete excess volume of 10.08 cm3 of mercury should have overflown the container, but due to the expansion of glass, the capacity of mercury containment increases and so a lesser amount of mercury flows out.

The amount of mercury that actually flowed out = 8.90 cm3.

So, the expansion of the glass container = 10.08-8.90 = 1.18 cm3.

Using the formula for coefficient of expansion,

coefficient of volume expansion of glass = 1.18/(1000 * 56) = 2.10* 10^-5 per degree Please rate

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Added Sat, 21 Nov '15
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