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A 396 kg piano slides 3.5 m down a 27 degree incline and is kept from accelerating by a man who is pushing back on it parallel to the incline (see figure). The effective coefficient of kinetic friction is 0.40.


(a) Calculate the magnitude of the force exerted by the man.
(b) Calculate the work done by the man on the piano.
(c) Calculate the work done by the friction force.
(d) Calculate the work done by the force of gravity.
(e) Calculate the net work done on the piano.
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Added Fri, 03 Jul '15
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A 396 kg piano slides 3.5 m down a(n) 27 degree incline and is kept from accelerating by a man who is pushing back on it parallel to the incline (see figure). The effective coefficient of kinetic friction is 0.40.

(a) The force exerted by the man.
= m g (sin ? - ? cos ?) = 396*9.8*(sin 27 ?- 0.40* cos 27?)
= 379.7 N

(b) The work done by the man on the piano.
=Force * distance = 379.7*3.5 = 1328.95 J

(c) The work done by the friction force.
=Force * distance = ?mg cos ? * 3.5
= 0.40*396*9.8 cos 27* 3.5 = 4853.2 J

(d) The work done by the force of gravity.
396*9.8*(sin 27)* 3.5 = 6182.J

(e) The net work done on the piano.
1328.95 + 4853.2 = 6182. J
Edit
Added Fri, 03 Jul '15
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