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A 100uF capacitor is charged to a potential difference of 50V. How much energy is stored? B) What is the approximate capacitance of a parallel plate capacitor having plate area of 10cm^2 and separated by a single sheet of ordinary paper. Don't forget about the dielectric constant, k, and watch the units. You'll also need to estimate the thickness of a sheet of paper (or measure it).
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Added Fri, 03 Jul '15
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(A) Energy = 1/2 * CV^2 = 1/2 * 100 * 10^(-6) * 50 = 0.0025 J

(B)The formula for a parallel plated capacitor is; C=Eo*Er*A/d. Leaving the permittivity aside, the formula could be considered as being; C=A/d. Hence, the capacitance is directly proportional to the area and indirectly proportional to the distance between the plates.

thickness of paper d= 0.1 mm

C = 10*10^(-4)/(0.1*10^(-3)) = 10 F
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