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An attacker at the base of a castle wall 3.60 m high throws a rock straight up with speed 4.00 m/s from a height of 1.60 m above the ground.

(a) If so, what is its speed at the top? If not, what initial speed must it have to reach the top?

in m/s

(b) Find the change in speed of a rock thrown straight down from the top of the wall at an initial speed of 4.00 m/s and moving between the same two points.

in m/s

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Added Wed, 11 Nov '15
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(a) The rock won't reach the top of the castle.

v = [2*(9.8)*(2)]1/2 = 6.264 ms-2

(b) 4*t + 0.5*9.8*t2 = 2

t = 0.35 sec

Final velocity, v = 4 + 9.8*0.35 = 7.43 ms-1

Change in velocity = 7.43 - 4 = 3.43 ms-1

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Added Wed, 11 Nov '15
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