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A spaceship is traveling through deep space towards a space station and needs to make a course correction to go around a nebula. The captain orders the ship to travel 3.1*10^6 kilometers before turning 70� and traveling 2.1*10^6 kilometers before assuming the path towards the space station. If the captain had not ordered a course correction, what would have been the magnitude and direction of the path of the spaceship if it had traveled through the nebula?

Whats the Ax, Ay, Bx, By? and how your got those and what is the answer

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Added Sun, 08 Nov '15
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Let's assume that the initial turn heads the spacecraft "east" and that the second turn heads toward the "northeast". The final position is

P = ( (3.1 + 2.1cos70�) i + 2.1sin70� j )*10^6 km

P = (3.818 i + 1.973 j) * 10^6 km

magnitude P = ?(3.818� + 1.973�) * 10^6km = 4.298 x 10^6 km

? = arctan(1.973/3.818) = 27.33�

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Added Sun, 08 Nov '15
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