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Water used for low country boil is accidentally converted to steam at 400K. The steam has a pressure of p=200,000Pa in a large volume of V=1000m3. What was the original volume of liquid water (before it turned to steam)? Use R=10J/molK, the mass density of liquid water of 1000kg/m3 and the molar mass of water M=0.02 kg/mol. (Hint: find the mass of the steam and use the density to find the volume of liquid water.)
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Added Fri, 03 Jul '15
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No of moles of water in steam (using ideal gas law)

n=PV/RT=200000*1000/10*400=50000 mol

Mass of water=moles*mol wt=50000*0.02=1000 kg

Volume of water= mass/density
=1000/1000
=1m3

Hence e. 1m3 is correct option.
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Added Fri, 03 Jul '15
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