A proton is initially at rest. After some time, a uniform electric field is turned on and the proton accelerates. The magnitude of the electric field is 1.36 105 N/C.
(a) What is the speed of the proton after it has traveled 3.00 cm?
(b) What is the speed of the proton after it has traveled 30.0 cm?
Speed of the proton = (2*a*s)^1/2
where a is the acceleration and s is the distance
=( 2 * qE/m * 3/100)^1/2
= 2 * 10^8 * 1.36105 * 3/100
=2.856 * 10^3 m/s