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A solid cylindrical disk has a radius of 0.45 m. It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a 15-N force is applied to the disk, perpendicular to its radius, the disk acquires an angular acceleration of 120 rad/s2. What is the mass of the disk?
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Torque: N = r x F = I alpha

Since r and F are perpendicular,
rF = (1/2 mr^2) (alpha)
m = 2F / (alpha r)
= 2 (15N) / (120 /s^2 * 0.45 m)
= 2*15/ (120 * 0.45) kg
= 0.55 kg

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