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A soccer ball with mass .42 kg is initially moving with speed 2.00 m/s. A soccer player kicks the ball, exerting a constant force of 40N in the same direction as the ball's motion. Over what distance must the player's foot be in contact with the ball to increase the ball's speed to 6.00 m/s?

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Using the work energy theorem:

m = 0.42 kg

vi = 2 m/s

vf = 6 m/s

F = 40 N

work = F.d = delta_KE

delta_KE = (1 / 2) * m * vf ^ 2 - (1 / 2) * m * vi ^ 2

delta_KE = 6.72 J

d = delta_KE / F

d=6.72/40

d = 0.168 m

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