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The 1 kg white ball in the figure has a speed of 1.78 m/s and the 1 kg yellow ball is at rest prior to an elastic glancing collision. After the collision the white ball scatters at 60 degrees. To the nearest degree, measured counterclockwise from east, what angle does the yellow ball scatter?

Added Thu, 02 Jul '15

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Here As the Collision is Elastic

Let u and v are the Final velocities of White and Yellow Balls

Momentum remains Conserved in Both Direction

SO Along Horizontal Direction

1*1.78 = 1*u*Cos(60) + 1*v*Cos(theta)

Also along Vertical Direction

1*u*Sin(60) = 1*v*Sin(theta)

Also Kinetic Energy remains Conserved

Therefore

0.5*1*1.78^2 = 0.5*1*u^2 + 0.5*1*v^2

So from these Equations we get

u =Final Velocity of White Ball = 0.89 m/sec

v = Final Velocity of Yellow Ball = 1.54 m/sec

theta = 30 degree Clockwise from East

So Required Angle = 360 - 30

= 330 degree Counterclockwise to the East

Added Thu, 02 Jul '15

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