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At a given instant, a particle with a mass of 4.50*10^-3kg and a charge of 3.60*10^-8C has a velocity with a magnitude of 1.50*10^5m/s in the +y direction. It is moving in a uniform magnetic field that has magnitude 0.800T and is in the -x direction.

Part A: What is the direction of the magnetic force on the particle?

Part C: What is the direction of the resulting acceleration of the particle?
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for direction

F=q*(V X B)

and V is towards j and B is towards -i

so j X (-i) =-k

a)so force in negative Z-direction (ans)

c)accleration is ame as force ,ie;  negative Z-direction (ans)
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