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A rookie quarterback throws a football with an initial upward velocity component of 15.2m/s and a horizontal velocity component of 18.1m/s . Ignore air resistance.

Part A

How much time is required for the football to reach the highest point of the trajectory?

Part B

How high is this point?

Part C

How much time (after it is thrown) is required for the football to return to its original level?

Part D

How does this compare with the time calculated in part (a).

Part E

How far has it traveled horizontally during this time?

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it's a problem of projectile motion

time of flight = 2*u(y)/g = 2*15.2/9.81 = 3.099 sec.

Horizontal range = 2*u(x)*u(y)/g = 2*15.2*18.1/9.81 = 56.089m

maximum height = u(y)^2/2g = 11.776m

A) time required to reach mximu heigth of trajectory = 1/2 of time of flight = 1.549s

B) maximum height = 11.766m

c) time of flight = 3.099s

d) it is double of one calculated in a)

e) horizontal range = 56.089m
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