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A rod 16.0 cm long is uniformly charged and has a total charge of -23.0 µC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 40.0 cm from its center
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Added Wed, 01 Jul '15
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E = kQ/D(D+L)

where Q = -23 �C, D = 0.4 - 0.16 = 0.24 m, L = 0.16 m

so E = (9 x 109) x(-23) / (0.24(0.4)) = (9 x 109) x(-23 x 10-6) / 0.096 = - 2.156 x 106 C/m2  

E is pointing towards the center of the rod (assuming that the rod is lying flat along the x-axis)
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