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A ball of mass 100 g travels toward a catcher of a ballistic pendulum of length 1.0 m. The mass of the catcher is 200 g. Assume that all the mass of the pendulum is in the catcher. The ball and the catcher collide and stick together. Their speed after the collision is 1.2 m/s. The ball / catcher system swings together and is vauch by a ratchet. The gravitational acceleration on earth is g = 9.81 m/s^2

a) What is the velocity of the ball before the collision?

b) What is the change in the momentum of the ball during the collision?

c) At what height is the ball/ caycher system caught by the ratchet?

d) How much energy is lost in the collision?
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Added Mon, 29 Jun '15
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a)momentum conservation
0.1*V=(0.1+0.2)*1.2
V=3.6 m/sec

b)change in momentum of ball
=0.1(3.6-1.2)
=0.24 Kgm/sec

c)height =V^2/2g
=1.2*1.2/2*9.8
=0.073 m 

d)energy lost
=0.5*0.1*3.6*3.6 -0.5*0.3*1.2*1.2
=0.432 J 

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Added Mon, 29 Jun '15
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