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Paleontologists estimate that if a Tyrannosaurus rex were to trip and fall, it would have experienced a force of approximately 260,000 N acting on its torso when it hit the ground.

A: Assuming the torso has a mass of 3800 kg, find the magnitude of the torso's upward acceleration as it comes to rest. (For comparison, humans lose consciousness with an acceleration of about 7 g.)

B: Assuming the torso is in free fall for a distance of 1.47 m as it falls to the ground, how much time is required for the torso to come to rest once it contacts the ground?
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a)
a = (F-mg)/m
a = 260000/3800 - 9.81 = 58.611m/s^2

b)
We need the speed it had as it hit the ground
Apply vf2 = vo2 + 2ad
vf2 = 0 + 2(9.8)(1.47)
vf = 5.4 m/s

Now use that for the stopping information
vf = vo + at
0 = 5.4 + 59(t)
t = .092 sec

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