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The following expression for the acceleration due to gravity works well for objects near the Earth's surface (G is the gravitational constant, Me is the mass of the Earth, and Re is the radius of the Earth):

g=(GM_e)/(R_e^2 )

Use the above equation to calculate the gravitational acceleration at an altitude of 100,000 meters above the Earth. By what percentage is this acceleration different from that on the Earth's surface?
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Added Sat, 29 Aug '15
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G = 6.67384 � 10-11 m3 kg-1 s-2 M_e = 5.97219 � 1024 kg and   R_e = 6378.1 km

at h=100,000 m , g= (GM_e)/( (R_e + h)^2 ) =9.4976 m/s^2

gravity at earth surface 9.80665 m/s2

% change= (9.80665 - 9.4976) / 9.80665

= 3.154
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