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For the circuit shown , determine the value of " a" (alpha) that makes the interconnections valid. Assume that V = 4V , I1 = 10A , and I2 = 10A . Express your answer to two significant figures.

? = V/A

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Now ,

Both are connected in parallel so ,

$V_{AF} = V_{BE}$

$\alpha I_{x} = V$

At point B

Net curret = 0

$I_{x} + I_{2} = 0$

$I_{x} = - I_{2}$

$I_{x} = - 10A$

Using above equation

$\alpha I_{x} = V$

$\alpha\times (-10) = 4$

$\alpha = -\frac{4}{10} = -0.4$

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