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Two electrons in a vacuum exert force of F = 4.11E-08 N on each other. They are then moved such that they are separated by x = 9.4 times their original distance.

a)What is the force that the electrons experience at the new distance, Fn, in newtons?

b)How far apart were the electrons originally in meters?
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since force is inversely proportional to square of distance between charges

new force = 4.11E-08/9.4^2 = 4.65*10^-10 N

original distance

4.11*10^-8 = 9*10^9 * (1.6*10^-19)^2/d^2

d = 7.487*10^-11 m

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