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A baseball is hit almost straight up into the air with a speed of about 16 m/s.
a.) How high does it go?
b.) How long is it in the air?S
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when we hit the ball we transfer energy from bat to the ball , and within ball its energy is kinetic energy, when it goes up into the air its potential energy become increasing and so its kinetic will decrease according to conservation of energy and eventually it is zero at this moment potential energy is maximum so the height is also maximum.

0.5m v^2 = mgh

0.5 *16*16 = 9.8* h

so h = 1.33 m

SECOND PART

as the motion is kinetic motion in one dimensional

so, time to go maximum height , t1

as, v= u+at here a= -g because acceleration is acceleration due to gravity which always act   downward

v=0 at maximum height

so t1 = u/g = 16/9.8 = 1.63 s

as the time taken to reach maximum height is equal to time taken to come back to ground from maximum height.

so total time taken = 2*t1 = 2*1.63 =3.26 s
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