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A hot-air balloon is rising upward with a constant speed of 2.00 m/s. When the balloon is 3.00 m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground?
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The initial velocity of the compass is 2 m/s upwards

Now we can use this equation:

s = s0 + Vi * t - 1/2 g*t^2

s0 = 3 m
Vi is the initial velocity, and t is time

we want to know what t is when s = 0 :

0 = 3+ 2t - 0.5*9.8*t^2

= 3 + 2t - 4.9 * t^2

t = 1.01272 sec
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