A tennis ball on Mars, where the acceleration due to gravity is 0.379 of a g and air resistance is negligible, is hit directly upward and returns to the same level 6.60s later.
1- How high above its original point did the ball go?
2- How fast was it moving just after being hit?
ball returns the same level at 6.6 sec
so reaches highest piont at 3.3 sec
v = u -.379gt v= 0
u = .379*9.8*3.3
this is the speed with which it was travelling after hit
v^2 = u^2 -2*.379*9.8*s
s = 20.221 m