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A parallel-plate capacitor has plates of area 0.40 m2 and plate separation of 0.20 mm. The capacitor is connected across a 9.0-V potential source. (?0 = 8.85 * 10-12 C 2/N ? m2)
(a) What is the magnitude of the electric field between the plates?
(b) What is the capacitance of the capacitor?
(c) What is the magnitude of the charge on each plate of the capacitor?
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C = e0*area/separation
V = Q/C

E = V/separation = Q/(e0*area)
E = 9/0.2*10^-3 = 45*10^3 V/m

C = 8.85*10^-12*0.4/0.2*10^-3
= 1.77 *10^-8 F

Q = C*V
= 1.77*10^-8 *9
= 1.593 *10^-7 C
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