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A 18 cm tall object is placed in front of a concave mirror with a radius of 33 cm. The distance of the object to the mirror is 96 cm. Calculate the focal length of the mirror. Tries 0/12 Calculate the image distance. Tries 0/12 Calculate the magnification of the image (Remember, a negative magnification corresponds to an inverted image). Tries 0/12 Calculate the magnitude of the image height.
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Hence focal length= R/2= 33/2= 16.5 cm

Object distance u= -96cm

Hence we have mirror formula

1/f= 1/v+1/u

1/-16.5= 1/v-1/96

v= - 19.92 = 20 cm

magnification m= -v/u= 20/-96= - .207

hence the image formed is inverted

hi/ho= m

hi= m*ho= -.20*18= -3.73 cm

negttive sign shows that the image formed is inverted
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