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A rod 71.0 cm long moves in a plane perpendicular to a magnetic field of 430 G. The velocity of the rod is perpendicular to its length. Find the speed of the rod if the potential difference between the ends is 4.90 V.

Added Thu, 25 Jun '15

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Motional EMF is given as e=BLv ------------ (1), here B is magnetic field , L is length of rod , v is velocity of rod perpendicular to magnetic field.

Now L = 71 cm = 0.71 m, B = 430G = 430 x 10-4 T (One gauss equals 1×10?4 tesla )

potential difference between the ends of rod is 4.90 V. Therefore e = 4.90 V

Putting all the values in (1) we get

speed v = 160.49 m/s

Added Thu, 25 Jun '15

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