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A circus performer stretches a tightrope between two towers. He strikes one end of the rope and sends a wave along it toward the other tower. He notes that it takes the wave 0.795 s to reach the opposite tower, 20.0 m away. If a 1.00-m length of the rope has a mass of 0.250 kg, find the tension in the tightrope. N

Added Fri, 14 Aug '15

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the speed of the wave v = 20 m/0.795 s = 25.16 m/s

v = sqrt(T/p) where t is tension, p is the linear density, equal to 0.250 kg/m

so T = p*v^2 = 0.250 * 25.16^2 = 158.26 N

v = sqrt(T/p) where t is tension, p is the linear density, equal to 0.250 kg/m

so T = p*v^2 = 0.250 * 25.16^2 = 158.26 N

Added Fri, 14 Aug '15

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