ToughSTEM
Sign Up
Log In
ToughSTEM
A question answer community on a mission
to share Solutions for all STEM major Problems.
Cant find a problem on ToughSTEM?
0
The figure depicts a simplistic optical fiber: a plastic core (n_1 = 1.58) is surrounded by a plastic sheath (n_2 = 1.44). A light ray is incident on one end of the fiber at angle theta. The rays is to undergo total internal reflection at point A, where it encounters the core-sheath boundary. (Thus there is no loss of light through that boundary.) What is the maximum value of theta that allows total internal reflection at A?


Edit
Added Thu, 25 Jun '15
Community
1
Comment
Add a Comment
Solutions
0
The critical angle for total internal reflection at A is sin?1(1.44/1.58) = 65.698 deg

. Using trigonometry, the angle
at the air/glass interface is thus 90 ? 65.698= 24.302

. Using Snell’s law, 1 sin(theta) = 1.58* sin(24.302), the maximum value of

theta that allows total internal reflection at A is 40.54 deg

Edit
Added Thu, 25 Jun '15
Community
1
Comment
Add a Comment
Add Your Solution!
Close

Click here to
Choose An Image
or
Get image from URL
GO
Close
Back
Add Image
Close
What URL would you like to link?
GO
α
β
γ
δ
ϵ
ε
η
ϑ
λ
μ
π
ρ
σ
τ
φ
ψ
ω
Γ
Δ
Θ
Λ
Π
Σ
Φ
Ω
Copied to Clipboard

Add Your Solution
Sign Up
to interact with the community. (That's part of how we ensure only good content gets on ToughSTEM)
OR
OR
ToughSTEM is completely free, and its staying that way. Students pay way too much already.
Almost done!
Please check your email to finish creating your account!
Welcome to the Club!
Choose a new Display Name
Only letters, numbers, spaces, dashes, and underscores, are allowed. Can not be blank.
Great! You're all set, .
A question answer community on a mission
to share Solutions for all STEM major Problems.
Why
The Purpose
How
The Community
Give Feedback
Tell us suggestions, ideas, and any bugs you find. Help make ToughSTEM even better.