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An RLC circuit such as that of Figure (a) has R = 4.17 Ohm, C - 29.4 uF, L = 0.865 H, and e_m = 26.3V.

(A) At what angular frequency w_d will the current amplitude have its maximum value, as in the resonance curves of figure (b)?

(B) what is this maximum value?

At what (C) lower angular frequency w_d1 and (D) higher angular frequency w_d2 will the current amplitude be half this maximum value?

(E) What is (w_d2 - w_d1)/w_d, the fractional half-width of the resonance curve for this circuit?

Edit
Added Thu, 25 Jun '15
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Xc=1/WC
Xl=WL
impedence of ciruit =R+(Xc-Xl)j
Current in max when impedence is min
=> Xc=Xl
=> Wd=1/sqrt(LC)=198.07

b)
Current, Max : 26.3/R=6.29A

c)For half its magnitude :
impedence=twice at peak
=> impedence= sqrt(R^2+(Xc-Xl)^2)
=>
R^2+(wL-1/wC)^2=2*4.18^2
17.47+(w*0.867-34013/w)^2=34.944

(w*0.867-34013/w)^2=17.47
=>
w*0.867-34013/w=4.18

this gives w=200.5 , 195.671
c) lower freq=195.671
d) higher=200.5
e) (200.5-195.671)/198.07
=0.024
Edit
Added Thu, 25 Jun '15
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