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A convex mirror has a focal length of magnitude f. An object is placed in front of this mirror at a point 2/3 f from the face of the mirror. The image will appear

upright and reduced.
inverted and enlarged.
upright and enlarged.
behind the mirror.
inverted and reduced.

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apply 1/f = 1/u +1/v

or f = uf/(u+v)

fhere u = 2f/3

1/v = 1/f - 1/u

v = uf/(u-f)

v = 2f/3 * f/(2/3-1)f

v = 2f/3 * 3/1

v = 2f so answer is upright and enlarged.
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