The Z,A =(3, 6 ) for reactant
Amount of energy relesed for this reaction will be
Sum of the masses of reactants = 14.0067 a.m.u(N)+ 1.0079 a.m.u(H) = 15.0146
Sum of the masses of products =10.811(B) amu + 6.941(X) amu = 17.752
Therefore, ?M = Sum of the masses of products � Sum of the masses of reactants
= 17.752 � 15.0146 = 2.7374a.m.u.
As there is increase of mass, hence energy is being absorbed .
The value of Q will be therefore negative i.e.
Q = 2.7374 a.m.u.X 931.5 MeV/a.m.u = 2549.8881 = 2550 MeV
Hence the above reaction is endogenic .
To conserve both momentum and energy, incoming particles must have a minimum amount of kinetic energy, called the threshold energy
m is the mass of the incoming particle
M is the mass of the target particle
If the energy is less than this amount, the reaction cannot occur
KE min = (1+ 1.0079 a.m.u/14.0067 a.m.u(N))|Q|
KE min = 2733.4939 MeV