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The two wires shown in the figure below are separated by d = 10.09 cm and carry currents of I = 5.35 A in opposite directions. (a) Find the magnitude and direction of the net magnetic field at a point midway between the wires. magnitude direction (b) Find the magnitude and direction of the net magnetic field at point p1, 10.9 cm to the right of the wire on the right. magnitude direction (c) Find the magnitude and direction of the net magnetic field at point p2, 2d = 21.8 cm to the left of the wire on the left. magnitude direction

Added Fri, 07 Aug '15

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The formula that applies here is B = uI/2pir from each wire.

Part A)

Right in the middle, the B fields will add, and they are the same, so...

B = 2(4pi X 10-7)(5.35)/2pi(.0545)

B = 3.93 X 10-5 T (39.3 uT) into the page

Part B)

At Point P1, the fields will subtract

B = (4pi X 10-7)(5.35)/2pi(.109) - (4pi X 10-7)(5.35)/2pi(.218)

B = 4.91 X 10-6 T (4.91 uT) Out of the page

Part C)

At Point P2, the fields will subtract

B = (4pi X 10-7)(5.35)/2pi(.218) - (4pi X 10-7)(5.35)/2pi(.327)

B = 1.64 X 10-6 T (1.64 uT) Out of the page

Added Fri, 07 Aug '15

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