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A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. A varying force F(t)=6.00t2 - 4.00t+3.00 is acting on the particle between t=0.00 seconds and t=5.00 seconds. Find the speed v of the particle at t=5.00 seconds.
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$v = Integral ( F / m ) dt$

$= \int_{0}^{5} (6t^2 - 4t + 3 ) / 5 dt$

$= 1/5 * ( 2t^3 - 2t^2 + 3t) | ( 0,5)$

$= 1/5 * ( 250 - 50 + 15)$

$= 215/5$

$= 43 m/s$

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Edited Wed, 06 Apr '16
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