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A 21-cm-long, zero-resistance wire is pulled outward, on zero-resistance rails, at a steady speed of 1.0m/sin a 0.10T magnetic field (See the figure). On the opposite side, a 1.0? carbon resistor completes the circuit by connecting the two rails. The mass of the resistor is 74mg.


a) What is the induced current in the circuit?

b) How much force is needed to pull the wire at this speed?

c) How much does the temperature of the carbon increase if the wire is pulled for 10 s? The specific heat of carbon is 710J/kg??C

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Added Fri, 07 Aug '15
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acc is 0 so F=BIL
also current I is BVL/R
I=.021A
F=.1*.021*.21=4.41*10^-4N
power= I^2*R
=4.41*10^-4J/sec
so for 10 sec 4.41*10^-3J
energy=mass*s*change in temp
=74*10^-3*710*T
T comes out to be 8.3*10^-5
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Added Fri, 07 Aug '15
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