ToughSTEM
Sign Up
Log In
ToughSTEM
A question answer community on a mission
to share Solutions for all STEM major Problems.
Cant find a problem on ToughSTEM?
0
The figure (Figure 1) shows a small plant near a thin lens. The ray shown is one of the principal rays for the lens. Each square is 2.3cm along the horizontal direction, but the vertical direction is not to the same scale. Use information from the diagram to answer the following questions.


A) What is the focal length of the lens?
f=___________cm

B) Calculate where the image should be.
s'=__________cm
Edit
Added Fri, 07 Aug '15
Community
1
Comment
Add a Comment
Solutions
0
A) focal length=2.3*5=11.5cm

B) now f=-11.5 and u=-2.3*8=-18.4

so using lens formula we get 1/v-1/u=1/f

so, 1/v=1/f+1/u=-(1/11.5+1/18.4)

so v=-7.07cm
Edit
Added Fri, 07 Aug '15
Community
1
Comment
Add a Comment
Add Your Solution!
Close

Click here to
Choose An Image
or
Get image from URL
GO
Close
Back
Add Image
Close
What URL would you like to link?
GO
α
β
γ
δ
ϵ
ε
η
ϑ
λ
μ
π
ρ
σ
τ
φ
ψ
ω
Γ
Δ
Θ
Λ
Π
Σ
Φ
Ω
Copied to Clipboard

Add Your Solution
Sign Up
to interact with the community. (That's part of how we ensure only good content gets on ToughSTEM)
OR
OR
ToughSTEM is completely free, and its staying that way. Students pay way too much already.
Almost done!
Please check your email to finish creating your account!
Welcome to the Club!
Choose a new Display Name
Only letters, numbers, spaces, dashes, and underscores, are allowed. Can not be blank.
Great! You're all set, .
A question answer community on a mission
to share Solutions for all STEM major Problems.
Why
The Purpose
How
The Community
Give Feedback
Tell us suggestions, ideas, and any bugs you find. Help make ToughSTEM even better.