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The figure (Figure 1) shows a small plant near a thin lens. The ray shown is one of the principal rays for the lens. Each square is 2.3cm along the horizontal direction, but the vertical direction is not to the same scale. Use information from the diagram to answer the following questions.

A) What is the focal length of the lens?
f=___________cm

B) Calculate where the image should be.
s'=__________cm
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A) focal length=2.3*5=11.5cm

B) now f=-11.5 and u=-2.3*8=-18.4

so using lens formula we get 1/v-1/u=1/f

so, 1/v=1/f+1/u=-(1/11.5+1/18.4)

so v=-7.07cm
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