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A proud deep-sea fisherman hangs a 64.5-kg fish from an ideal spring having negligible mass. The fish stretches the spring 0.110 m. (a) Find the force constant of the spring. N/m The fish is now pulled down 5.70 cm and released. (b) What is the period of oscillation of the fish? s (c) What is the maximum speed it will reach? m/s

Added Fri, 07 Aug '15

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A) k = F/x = mg/x = 64.5*9.8/0.11 = 5746.36 N/m ...

B) T = 2*pi*sqrt(m/k) = 0.665 sec...

C) Vmax = A*2*pi/T = 0.538 m/sec

Added Fri, 07 Aug '15

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