ToughSTEM
ToughSTEM
A question answer community on a mission
to share Solutions for all STEM major Problems.
Cant find a problem on ToughSTEM?
0
On a frictionless, horizontal air table, puck A (with mass 0.250kg ) is moving toward puck B (with mass 0.400kg ), which is initially at rest. After the collision, puck A has a velocity of 0.150m/s to the left, and puck B has a velocity of 0.630m/s to the right

Part A

What was the speed of puck A before the collision?

Part B

Calculate the change in the total kinetic energy of the system that occurs during the collision.
Edit
Community
1
Comment
Solutions
0
a) 0.250 vi = 0.250kg * -0.150m/s + 0.400kg * 0.630m/s

= 0.858 m/s

b)

ki = 1/2 * 0.250*(0.858)^2 = 0.092 J

kf =1/2 * 0.250*(0.150)^2+1 /2 * 0.400*(0.63)^2    = 0.0823

kf-ki = 0.0097 J
Edit
Community
1
Comment
Close

Choose An Image
or
Get image from URL
GO
Close
Back
Close
What URL would you like to link?
GO
α
β
γ
δ
ϵ
ε
η
ϑ
λ
μ
π
ρ
σ
τ
φ
ψ
ω
Γ
Δ
Θ
Λ
Π
Σ
Φ
Ω
Copied to Clipboard

to interact with the community. (That's part of how we ensure only good content gets on ToughSTEM)
OR
OR
ToughSTEM is completely free, and its staying that way. Students pay way too much already.
Almost done!
Welcome to the Club!
Choose a new Display Name
Only letters, numbers, spaces, dashes, and underscores, are allowed. Can not be blank.
Great! You're all set, .
A question answer community on a mission
to share Solutions for all STEM major Problems.
Why
The Purpose
How
The Community
Give Feedback
Tell us suggestions, ideas, and any bugs you find. Help make ToughSTEM even better.